# Line slope calculator 2x+y=11

**Straight line given by points A[3; 5] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = -2x+11

**Canonical form of the line equation:**2x+y-11 = 0

**Parametric form of the line equation:**

x = t+3

y = -2t+5 ; t ∈ R

**Slope:**m = -2

**Slope angle of line: φ =**-63°26'6″ = -1.1071 rad

**X intercept:**x

_{0}= 5.5

**Y intercept:**y

_{0}= q = 11

**Distance line from the origin:**d

_{0}= 4.9193

**The length of the segment AB: |AB| =**2.2361

**Vector: AB =**(1; -2)

**Normal vector: n =**(2; 1)

**Midpoint of the segment AB: M =**[3.5; 4]

**Perpendicular Bisector equation:**x-2y+4.5 = 0

**Vector OA = (3; 5) ; |OA| = 5.831**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 27**

**Angle ∠ AOB = 22°9'59″ = 0.3869 rad**